Four diodes, one direction.

How do four diodes keep AC output flowing one way?

Setting up the mechanism…

Average DC voltage: 0.00V
Average load current: 0.00mA
Ripple frequency: 100.00Hz

Load polarity: Positive on both half cycles

Fit all four bridge diodes, source and load

How do four diodes keep AC output flowing one way?

A diagonal diode pair conducts on each half cycle. The pair changes when the source reverses, but the current through the load keeps the same direction.

Vout(t) = max(0, |√2 Vrms sin(2πft)| − 2Vd)

What this model simplifies

Sinusoidal source, four ideal diodes with a fixed forward drop, resistive load and no smoothing capacitor. Reported output is the average of the full-wave waveform, not RMS.

Read the source · analog.com ↗

Put it to work.

Deliver at least 90 mA average with the same output polarity on both half cycles.

Make it work.

Compare load polarity during opposite AC half cycles.

Run

Fine adjustments 4

AC RMS voltageV

Each diode dropV

Load resistanceΩ

AC frequencyHz

Four diodes, one direction.

How do four diodes keep AC output flowing one way?

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Figuvo is a place to look inside everyday things, build a connection, and discover the idea behind them.

177 interactive experiments. Each has a working model and a challenge to test what you found.

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Everyday electrical

Four diodes, one direction.

How do four diodes keep AC output flowing one way?

Setting up the mechanism…

Average DC voltage: 0.00V
Average load current: 0.00mA
Ripple frequency: 100.00Hz

Load polarity: Positive on both half cycles

Fit all four bridge diodes, source and load

How do four diodes keep AC output flowing one way?

A diagonal diode pair conducts on each half cycle. The pair changes when the source reverses, but the current through the load keeps the same direction.

Vout(t) = max(0, |√2 Vrms sin(2πft)| − 2Vd)

What this model simplifies

Sinusoidal source, four ideal diodes with a fixed forward drop, resistive load and no smoothing capacitor. Reported output is the average of the full-wave waveform, not RMS.

Read the source · analog.com ↗

Put it to work.

Deliver at least 90 mA average with the same output polarity on both half cycles.

Make it work.

Compare load polarity during opposite AC half cycles.

Run

Fine adjustments 4

AC RMS voltageV

Each diode dropV

Load resistanceΩ

AC frequencyHz